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When I was Caulfield’s age walking to school after a snowstorm, if the sidewalk was shoveled, I would tromp through the snow alongside it. Wasn’t the only one.
Easily. Lois’s position is 4.9t^2 for t >= 0. Superman’s is 12×4.9(t – 0.75)^2 for t >= 0.75. Solving for t gives
4.9t^2 = 12×4.9 (t – 0.75)^2
t^2 = 12(t – 0.75)^2
t = sqrt(12) (t – 0.75)
(taking the solution where t > 0.75)
0.75 sqrt(12) = t sqrt(12) – t
t = 0.75 sqrt(12)/[sqrt(12) – 1] = 1.054 seconds.
Their position then is 4.9 Ă— 1.054^2 = 5.44 meters below the top of the building, plenty of time for Superman to decelerate before they reach the ground.
Old riddle, time gap from northbound to southbound is one-fifth that of southbound to northbound (if Alice is north), so southbound buses arrive five minutes after northbound buses.Bob should flip a coin and take the second bus half the time.
When I was Caulfield’s age walking to school after a snowstorm, if the sidewalk was shoveled, I would tromp through the snow alongside it. Wasn’t the only one.