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“12 miles”? Would that be statute miles (1.609344 km) or nautical miles (1.852 km) or Chinese miles (0.500 km)?
Without its elitist trappings, this is a common math problem, usually involving two trains and a fly. Assuming nautical miles, and a closing speed of 10+14=24 nautical miles per hour (a knot is one nautical mile per hour), clearly the yachts would meet half an hour after departure, with a bunch of assumptions, such as simultaneous departure and heading for each other.
That’s the easy way to figure it—geniuses do it differently: https://mathworld.wolfram.com/TwoTrainsPuzzle.html
“12 miles”? Would that be statute miles (1.609344 km) or nautical miles (1.852 km) or Chinese miles (0.500 km)?
Without its elitist trappings, this is a common math problem, usually involving two trains and a fly. Assuming nautical miles, and a closing speed of 10+14=24 nautical miles per hour (a knot is one nautical mile per hour), clearly the yachts would meet half an hour after departure, with a bunch of assumptions, such as simultaneous departure and heading for each other.
That’s the easy way to figure it—geniuses do it differently: https://mathworld.wolfram.com/TwoTrainsPuzzle.html