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They will meet in one half hour at the point five miles from Todd’s island and seven miles from Mitch’s. The wind is generally blowing from Mitch’ island towards Todd’s, or Mitch owns the yacht with the better motor.
“12 miles”? Would that be statute miles (1.609344 km) or nautical miles (1.852 km) or Chinese miles (0.500 km)?
Without its elitist trappings, this is a common math problem, usually involving two trains and a fly. Assuming nautical miles, and a closing speed of 10+14=24 nautical miles per hour (a knot is one nautical mile per hour), clearly the yachts would meet half an hour after departure, with a bunch of assumptions, such as simultaneous departure and heading for each other.
That’s the easy way to figure it—geniuses do it differently: https://mathworld.wolfram.com/TwoTrainsPuzzle.html
Ken Norris Premium Member over 3 years ago
They will meet in one half hour at the point five miles from Todd’s island and seven miles from Mitch’s. The wind is generally blowing from Mitch’ island towards Todd’s, or Mitch owns the yacht with the better motor.
cherns Premium Member over 3 years ago
“12 miles”? Would that be statute miles (1.609344 km) or nautical miles (1.852 km) or Chinese miles (0.500 km)?
Without its elitist trappings, this is a common math problem, usually involving two trains and a fly. Assuming nautical miles, and a closing speed of 10+14=24 nautical miles per hour (a knot is one nautical mile per hour), clearly the yachts would meet half an hour after departure, with a bunch of assumptions, such as simultaneous departure and heading for each other.
That’s the easy way to figure it—geniuses do it differently: https://mathworld.wolfram.com/TwoTrainsPuzzle.html