It’s like those flashing popups that say “This is not a joke, you are the 100th visitor.” But only when that’s actually the truth, even if the scam didn’t know that.
As a challenge, I thought I might try to find a spinor representation of an icosahedron; I wondered if it could have a simple expression with pretty symmetry. While not very difficult to find, the expression was not very simple. It would have to have a form of P^p Q^q R^r, with each of P, Q, and R a rotation of 2pi/5 radians about a different axis; and p, q, and r as integers. The challenge is finding the right axes to use. One needs three rotation axes because an icosahedron has an odd (5-fold) rotational symmetry, so rotation about the Q axis alone cannot take the P axis to -P. With I representing the identity rotation (or no rotation), one can quickly find that rotation about axis P by 2pi/5 has the form [1-e^(2pi i/5))I/2 + (1+e^2p i/5)P/2], where P is a spinor for axis P in this expression.
Spoiler alert: In my next reply I will identify an axis Q for the next rotation.
Averagemoe about 3 years ago
It’s like those flashing popups that say “This is not a joke, you are the 100th visitor.” But only when that’s actually the truth, even if the scam didn’t know that.
Sugar Bombs 95 about 3 years ago
So, are there multiple unicorns out there with that name? Meaning Marigold’s not as special as she thinks?
codycab about 3 years ago
You know what would be funny for us but cruel irony for Marigold? If her sister Florence won an award.
Dirty Dragon about 3 years ago
Dolly Parton lost a Dolly Parton lookalike contest.
Susan00100 about 3 years ago
I wonder who else is up for that award.
iggyman about 3 years ago
Nostrils? “Navage” comes to mind!
mistie710 about 3 years ago
That’s sooooo last nostril!
Troglodyte about 3 years ago
There was an Oscar winner named Oscar (I googled it), so there’s hope yet for Mari!
Decepticomic about 3 years ago
I once won the Award at the Awardy Awards for Best Award. It wasn’t very rewarding.
scyphi26 about 3 years ago
I don’t even know where to start on this one, but I will say that this does seem very Unicorn.
The Wolf In Your Midst about 3 years ago
Unfortunately, about 90% of the answers in the FAQ are just “Unicorn!”.
celeconecca about 3 years ago
I still miss the “Heavenly Nostrils” title.
Major Matt Mason Premium Member about 3 years ago
I was thinking car insurance, myself.
Frer Squirrel about 3 years ago
As a challenge, I thought I might try to find a spinor representation of an icosahedron; I wondered if it could have a simple expression with pretty symmetry. While not very difficult to find, the expression was not very simple. It would have to have a form of P^p Q^q R^r, with each of P, Q, and R a rotation of 2pi/5 radians about a different axis; and p, q, and r as integers. The challenge is finding the right axes to use. One needs three rotation axes because an icosahedron has an odd (5-fold) rotational symmetry, so rotation about the Q axis alone cannot take the P axis to -P. With I representing the identity rotation (or no rotation), one can quickly find that rotation about axis P by 2pi/5 has the form [1-e^(2pi i/5))I/2 + (1+e^2p i/5)P/2], where P is a spinor for axis P in this expression.
Spoiler alert: In my next reply I will identify an axis Q for the next rotation.
jerrica.benton333 about 3 years ago
is that like the “Catch-her in the Oats Award”
Daeder about 3 years ago
I could have sworn the icosahedron said “You won initiative; it is now your turn. What would you like to do?”
The Better Player about 3 years ago
when you lose your own cojntext