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I’m sorry to contradict your extremely cool comment, but I’m pretty sure that e^(-i*π) = -1 (and in fact so is e^(i*π) ).  ( e^(-i*2π) and e^(i*2π) are indeed 1, but that isn’t nearly as cool).
Phatts almost 13 years ago
… sounds like “discussions” with wife …
InTraining Premium Member almost 13 years ago
NOW…… I have a irrational taste for pie…. ! ! !
revisages almost 13 years ago
at this rate, he’s running circles around the whole
a_hemant almost 13 years ago
Don’t worry. Everything is in an apple-π order !!!
RonaldDavis almost 13 years ago
What you say is true as far as it goes, but you haven’t finished. When you have finished, then you can say it’s that simple.
Strod almost 13 years ago
I’m sorry to contradict your extremely cool comment, but I’m pretty sure that e^(-i*π) = -1 (and in fact so is e^(i*π) ).  ( e^(-i*2π) and e^(i*2π) are indeed 1, but that isn’t nearly as cool).
ububobu almost 13 years ago
Note: Frank, Ernie and the third guy are 4068 decimal and 7744 octal. This is very significant!
willpittenger almost 13 years ago
PI isn’t irrational. Irrational numbers are those that are multiplied by the square root of -1, which we call i.
REDROCKER51 almost 13 years ago
i ate a piece of pie once…….that was hard…….wanna know why?…because i am a DUCK !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
iced tea almost 13 years ago
Here’s pi in your eye!
bmonk almost 13 years ago
Well, the Alephs are all infinite—just that some are bigger than others. And, there may, or may not, be “inaccessible Cardinals” out there too.